Jaslyn had
45 as many candy canes as Elijah. Elijah had
47 as many candy canes as Fred. If Fred had 152 more candy canes than Jaslyn, find the total number of candy canes that was shared among these 3 children at first.
Jaslyn |
Elijah |
Fred |
4x4 |
5x4 |
|
|
4x5 |
7x5 |
16 u |
20 u |
35 u |
Elijah is the repeated identity.
LCM of 5 and 4 = 20
Number of more candy canes that Fred had more than Jaslyn
= 35 u - 16 u
= 19 u
19 u = 152
1 u = 152 ÷ 19 = 8
Total number of candy canes
= 16 u + 20 u + 35 u
= 71 u
= 71 x 8
= 568
Answer(s): 568