There were 250 pears and persimmons in a fruit stall.
310 of the pears and
38 of persimmons were sold. Given that there were 187 pears and persimmons left, how many pears were there in the fruit stall at first?
|
Pears |
Persimmons |
Before |
10 u |
8 p |
Change |
- 3 u |
- 3 p |
After |
7 u |
5 p |
10 u + 8 p = 250 --- (1)
7 u + 5 p = 187 --- (2)
Make p the same.
(1)
x 5 50 u + 40 p = 1250 --- (3)
(2)
x 8 56 u + 40 p = 1496 --- (4)
(4) - (3)
56 u - 50 u = 1496 - 1250
6 u = 246
1 u = 246 ÷ 6 = 41
Number of pears at first
= 10 u
= 10 x 41
= 410
Answer(s): 410