Perry and Brandon had the same number of marbles. Perry gave away
34 of his marbles while Brandon gave away
35 of his marbles. Given that Perry gave away 12 marbles more than Brandon, how many marbles did Perry have at first?
| |
Perry's marbles |
Brandon's marbles |
| Before |
4x5 =
20 u |
5x4 =
20 u |
| Change |
- 3x5 =
- 15 u |
- 3x4 =
- 12 u |
| After |
1x5 =
5 u |
2x4 =
8 u |
The number of cards that Perry and Brandon each had at first is the same. Make the number of cards that Perry and Brandon each had at first the same. LCM of 4 and 5 is 20.
Number of marbles that Perry gave away more than Brandon
= 15 u - 12 u
= 3 u
3 u = 12
1 u = 12 ÷ 3 = 4
Number of marbles that Perry had at first
= 20 u
= 20 x 4
= 80
Answer(s): 80
