Container W has thrice as much water as Container V. If David adds 0.5 ℓ of water to Container W and 2.2 ℓ of water to Container V, both containers will have the same volume of water. Find the volume of water in Container W at first.
| |
V |
W |
| Before |
1 u |
3 u |
| Change |
+ 2.2 |
+ 0.5 |
| After |
1 u + 2.2 |
3 u + 0.5 |
Both containers have the same volume of water in the end.
3 u + 0.5 = 1 u + 2.2
3 u - 1 u = 2.2 - 0.5
2 u = 1.7
1 u = 1.7 ÷ 2 = 0.85
Volume of water in Container W at first
= 3 u
= 3 x 0.85
= 2.55 ℓ
Answer(s): 2.55 ℓ
