The table shows the distance Mr Yeo jogged each day over a period of 4 days. The distance Mr Yeo jogged follows a pattern. Based on the pattern, what is the distance Mr Yeo jogged on Day 10?
| Day |
1 |
2 |
3 |
4 |
| Distance jogged |
400 m |
525 m |
650 m |
775 m |
Pattern for the distance jogged:
Day 1: 400 + 0 x 125 = 400 m
Day 2: 400 + 1 x 125 = 525 m
Day 3: 400 + 2 x 125 = 650 m
Day 4: 400 + 3 x 125 = 775 m
Formula:
Distance jogged = 400 + (Day number - 1) x 125
Distance jogged on Day 10
= 400 + (10 - 1) x 125
= 400 + 9 x 125
= 1525 m
Answer(s): 1525 m
