A sum of $810 is divided among a group of people.
89 of the people receive $8 each,
12 of the remainder receive $5 each and the rest receive $2 each. How many people are there altogether?
$8 |
$5 |
$2 |
8 x 2 |
1 x 2 |
|
1 |
1 |
16 u |
1 u |
1 u |
|
$8 |
$5 |
$2 |
Number |
16 u |
1 u |
1 u |
Value |
$8 |
$5 |
$2 |
Total value |
128 u |
5 u |
2 u |
Fraction of people who did not receive $8
= 1 -
89 =
19 Fraction of the remainder who received $2
= 1 -
12 =
12 Fraction of people who received $5
=
19 x
12 =
118 Fraction of people who received $2
=
19 x
12 =
118Total amount of money received
= 128 u + 5 u + 2 u
= 135 u
135 u = 810
1 u = 810 ÷ 135 = 6
Number of people who received the money
= 16 u + 1 u + 1 u
= 18 u
= 18 x 6
= 108
Answer(s): 108