In a kiosk that sells blazers, 60 black blazers were sold and 50% of the remaining blazers that were sold were brown. Of the leftover, 60% of the blazers sold were red blazers and the rest were silver blazers. Given that the number of silver blazers sold was 10% of the total number of blazers sold, how many brown and silver blazers were sold altogether?
50% =
50100 =
12 60% =
60100 =
35 10% =
10100 =
110
Black |
Brown |
Red |
Silver |
60 |
1x5 |
1x5 |
|
|
3x1 |
2x1 |
9x2 |
1x2 |
10 u |
5 u |
3 u |
2 u |
The total number of red and silver shirts is the combined repeated identity. Make the total number of red and silver shirts the same. LCM of 1 and 5 is 5.
The number of silver shirts is repeated. Make the number of silver shirts the same. LCM of 2 and 1 is 2.
Number of black blazers
= 18 u - 5 u - 3 u
= 10 u
10 u = 60
1 u = 60 ÷ 10 = 6
Number of brown and silver blazers
= 5 u + 2 u
= 7 u
= 7 x 6
= 42
Answer(s): 42