At the office building, Storey C and Storey D had an equal number of chairs at first. If 8 chairs were removed from Storey D and 5 times as many chairs were removed from Storey C as Storey D, the number of chairs in Storey D would be 5 times as many as in Storey C. Find the number of chairs on each storey.
|
Storey C |
Storey D |
Before |
1 u |
1 u |
Change |
- 40 |
- 8 |
After |
1 u - 40 |
1 u - 8 |
Number of chairs removed from Storey C
= 5 x 8
= 40
Number of chairs on Storey C and Storey D at first is the same.
Number of chairs on Storey D is 5 times as many as Storey C in the end. If the number of chairs on Storey C increases by 5 times, the number of chairs on Storey C and Storey D will be the same.
5(1 u - 40) = 1 u - 8
5 u - 200 = 1 u - 8
5 u - 1 u = 200 - 8
4 u = 192
1 u = 192 ÷ 4 = 48
Number of chairs in each floor
= 1 u
= 48
Answer(s): 48