The number of red apples is the same as the number of green apples in a bag. After removing
14 of the apples, there were 26 red apples and 118 green apples left in the bag. Then, another 32 red apples and 32 green apples were removed and there were
512 of the apples left in the end. How many red apples were removed altogether?
| |
Red Apples |
Green Apples |
Total |
| Before |
1 p
96 |
1 p
96 |
12 u |
| Change 1 |
- ? (14 of the total) |
- 7 u |
| After 1 |
26 |
118 |
| Change 2 |
- 32 |
- 32 |
| After 2 |
80 |
5 u |
Number of apples left
= 26 + 118 - 32 - 32
= 80
5 u = 80
1 u = 80 ÷ 5 = 16
Total number of apples at first
= 12 u
= 12 x 16
= 192
Number of red apples at first
= 192 ÷ 2
= 96
Number of red apples removed at first
= 96 - 26
= 70
Total number of red apples removed
= 70 + 32
= 102
Answer(s): 102
