At a school sports festival, 14 of the participants were P5 and P6 students. 35 of the remaining participants were P3 and P4 students. The rest were P1 and P2 students in the ratio of 4 : 5 respectively. There were 95 more P5 and P6 students than P2 students. How many students were there at the school sports festival?
| P1 |
P2 |
P3 |
P4 |
P5 |
P6 |
Total |
| 3x15 |
1x15 |
4x15 |
| 2x9 |
3x9 |
|
|
| 4x2 |
5x2 |
|
|
|
|
|
| 8 u |
10 u |
27 u |
15 u |
60 u |
The total number of P1 and P2 students is the combined repeated identity. Make the total number of P1 and P2 students the same. LCM of 2 and 9 is 18.
The total number of P1, P2, P3 and P4 students is another combined repeated identity. Make the total number of P1, P2, P3 and P4 students the same. LCM of 45 and 3 is 45.
Number of more P5 and P6 students than P2 students
= 15 u - 10 u
= 5 u
5 u = 95
1 u = 95 ÷ 5 = 19
Total number of students at the sports festival
= 60 u
= 60 x 19
= 1140
Answer(s): 1140
