Mark, Reggie and Liam shared a sum of money. The amount received by Reggie was
34 the amount of money received by Liam. After Mark had given $45 to Reggie and $24 to Liam, Reggie gave $2 to Liam. In the end, 3 of them had the same amount of money. Find the difference between the amount of money that Mark and Reggie had at first.
|
Mark |
Reggie |
Liam |
Before |
3 u + 112 |
3 u |
4 u |
Change 1 |
- 45 |
+ 45 |
|
Change 2 |
- 24 |
|
+ 24 |
Change 3 |
|
- 2 |
+ 2 |
After |
3 u + 43 |
3 u + 43 |
4 u + 26 |
Amount that Reggie had in the end = 3 u + 43
Amount that Liam had in the end = 4 u + 26
Amount that Mark had at first
= 3 u + 43 + 45 + 24
= 3 u + 112
Amount that Reggie and Liam had in the end is the same.
3 u + 43 = 4 u + 26
4 u - 3 u = 43 - 26
1 u = 17
Amount that Mark and Reggie had in the end is the same.
Amount that Mark had in the end
= 3 u + 43
= 3 x 17 + 43
= 51 + 43
= $94
Amount that Mark had at first
= 94 + 45 + 24
= $163
Difference in the amounts between Mark and Reggie at first
= 163 - 51
= $112
Answer(s): $112