70% of the candies in Packet L were blueberry candies and the rest were cherry candies. Packet M had 25% more blueberry candies than Packet L and four times as many candies than the total number of candies in Packet L. Find the percentage of the cherry candies in Packet M that would need to be transferred into Packet L, so that there were an equal number of blueberry and cherry candies in Packet L.

	Packet L		Packet M
	Blueberry	Cherry	Blueberry	Cherry
	10 u		40 u
Before	7 u	3 u	8.75 u	31.25 u
Change		+ 4 u		- 4 u
After	7 u	7 u	8.75 u	27.25 u

70% = ⁷⁰₁₀₀ = ⁷₁₀
100 %+ 25% = 125%

 Total number of candies in Packet L
= 7 u + 3 u
= 10 u

Total number of candies in Packet M
= 4 x 10 u 
= 40 u

Number of blueberry candies in Packet M
= 125% x 7 u
=  ¹²⁵₁₀₀ x 7 u
= 8.75 u

Number of blueberry candies in Packet M
= 40 u - 8.75 u
= 31.25 u

Number of cherry candies to be transferred from Packet M to Packet L
= 7 u - 3 u
= 4 u

Percentage of candies to be transferred from Packet M
= ⁴_31.25 x 100%
= 12.8%

Answer(s): 12.8%