Will, Vincent and Daniel shared a bag of erasers. Vincent took 35 as many erasers as Daniel. Will took twice as many erasers as the total Vincent and Daniel took. After Will had given 37 to Vincent and 11 to Daniel, Vincent gave 7 to Daniel. In the end, all three of them had the same number of erasers. Find the difference between the number of erasers that Will and Vincent had at first.
| |
Vincent |
Daniel |
Will |
Total |
| Before |
3 u |
5 u |
16 u |
24 u |
| Change 1 |
+ 37 |
|
- 37 |
|
| Change 2 |
|
+ 11 |
- 11 |
|
| Change 3 |
- 7 |
+ 7 |
|
|
| After |
1x8 =
8 u |
1x8 =
8 u |
1x8 =
8 u |
3x8 =
24 u |
Total number of erasers that Vincent and Daniel had at first
= 3 u + 5 u
= 8 u
Number of erasers that Will had at first
= 2 x 8 u
= 16 u
The total number of erasers remains unchanged. Make the total number of erasers the same. LCM of 3 and 24 is 24.
Number of erasers that Daniel received from Vincent and Will
= 8 u - 5 u
= 3 u
3 u = 11 + 7
3 u = 18
1 u = 18 ÷ 3 = 6
Difference between the number erasers that Will and Vincent had at first
= 16 u - 3 u
= 13 u
= 13 x 6
= 78
Answer(s): 78
