At a school carnival, each woman received 3 packets of candy canes and each man received 5 packets of candy canes. Each accompanying child received 7 packets of candy canes.
37 of the people at the school carnival were child. The ratio of the number of women to the number of men at the carnival was 3 : 8. Given that only 2135 packets of candy canes were given away, how many people were there at the carnival?
Women |
Men |
Child |
4x11 = 44 u |
3x11 = 33 u |
3x4 = 12 u |
8x4 = 32 u |
33 u |
|
Women |
Men |
Child |
Number |
12 u |
32 u |
33 u |
Value |
3 |
5 |
7 |
Total Value |
36 u |
160 u |
231 u |
Fraction of the people who were adults
= 1 -
37=
47 The number of adults is the combined repeated identity. Make the number of adults the same. LCM of 11 and 4 is 44.
Number of packets of candy canes given away
= 12 u x 3 + 32 u x 5 + 33 u x 7
= 36 u + 160 u + 231 u
= 427 u
427 u = 2135
1 u = 2135 ÷ 427 = 5
Number of people at the carnival
= 44 u + 33 u
= 77 u
= 77 x 5
= 385
Answer(s): 385