A convenience store sold bacon, club and ham sandwiches. The ratio of the number of bacon sandwiches made to the total number of sandwiches made was 2 : 3. The ratio of the number of club sandwiches made to the total number of sandwiches made was 1 : 8. After the store sold some bacon sandwiches and made another 21 club sandwiches, there was an equal number of bacon, club and ham sandwiches left. Find the number of bacon sandwiches sold.
|
Bacon |
Club |
Ham |
Total |
Comparing bacon to total |
2x8 |
|
|
3x8 |
Comparing club to total |
|
1x3 |
|
8x3 |
|
16 u |
3 u |
5 u |
24 u |
|
Bacon |
Club |
Ham |
Total |
Before |
16 u |
3 u |
5 u |
24 u |
Change |
- 11 u |
+ 21 |
No change |
|
After |
1x5 = 5 u |
1x5 = 5 u |
1x5 = 5 u |
|
The total number of sandwiches is the same at first. Make the total number of sandwiches the same. LCM of 8 and 3 is 24.
Number of ham sandwiches remains the same at first and in the end. Make the number of ham sandwiches the same. LCM of 1 and 5 is 5.
Number of ham sandwiches
= 24 u - 16 u - 3 u
= 5 u
Number of bacon, club and ham sandwiches is the same in the end.
Number of club sandwiches = 3 u + 21
3 u + 21 = 5 u
5 u - 3 u = 21
2 u = 21
1 u = 21 ÷ 2 = 8
Number of bacon sandwiches sold
= 16 u - 5 u
= 11 u
= 11 x 8
= 88
Answer(s): 88