Tom, Xavier and Tim had the same number of balls. Tim gave 0.6 of his balls to Xavier. Then Xavier gave 0.25 of his balls to Tom. Finally, after Xavier gave 22 balls to Tim, he had the same number of balls as Tim. How many balls did Tim have at first?
| |
Tom |
Xavier |
Tim |
| Before |
1 u |
1 u |
1 u |
| Change 1 |
|
+ 0.6 u |
- 0.6 u |
| After 1 |
1 u |
1.6 u |
0.4 u |
| Change 2 |
+ 0.4 u |
- 0.4 u |
|
| After 2 |
1.4 u |
1.2 u |
0.4 u |
| Change 3 |
|
- 22 |
+ 22 |
| After 3 |
1.4 u |
1.2 u - 22 |
0.4 u + 22 |
Number of balls that Xavier gave to Tom
= 0.25 x 1.6 u
= 0.4 u
The number of balls that Xavier and Tim had in the end is the same.
1.2 u - 22 = 0.4 u + 22
1.2 u - 0.4 u = 22 + 22
0.8 u = 44
1 u = 44 ÷ 0.8 = 55
Number of balls that Tim had at first
= 1 u
= 55
Answer(s): 55
