Japheth had 80% fewer lollipops than Paul. After Paul gave 161 lollipops to Japheth, Japheth had ²₃ as many lollipops as Paul. How many lollipops did each of them have in the end?

1. Paul
2. Japheth

	Japheth	Paul	Total
Before	1x5 = 5 u	5x5 = 25 u	6x5 = 30 u
Change	+ 161	- 161
After	2x6 = 12 u	3x6 =  18 u	5x6 = 30 u

Number of lollipops that Japheth had at first in percentage
= 100% - 80%
= 20%

20% = ²⁰₁₀₀ = ¹₅

The total number of lollipops at first and in the end remains unchanged. Make the total number of lollipops the same. LCM of 5 and 6 is 30.

Number of lollipops that Paul gave to Japheth
= 25 u - 18 u
= 7 u

7 u = 161

1 u = 161 ÷ 7 = 23

Number of lollipops that Japheth had in the end
= 12 u
= 12 x 23
= 276

Number of lollipops that Paul had in the end
= 18 u
= 18 x 23
= 414

Answer(s): (a) 276; (b) 414