Bobby had 70% fewer sweets than Fred. After Fred gave 192 sweets to Bobby, Bobby had
56 as many sweets as Fred. How many sweets did each of them have in the end?
- Fred
- Bobby
| |
Bobby |
Fred |
Total |
| Before |
3x11 =
33 u |
10x11 =
110 u |
13x11 =
143 u |
| Change |
+ 192 |
- 192 |
|
| After |
5x13 =
65 u |
6x13 =
78 u |
11x13 =
143 u |
Number of sweets that Bobby had at first in percentage
= 100% - 70%
= 30%
30% =
30100 =
310 The total number of sweets at first and in the end remains unchanged. Make the total number of sweets the same. LCM of 11 and 13 is 143.
Number of sweets that Fred gave to Bobby
= 110 u - 78 u
= 32 u
32 u = 192
1 u = 192 ÷ 32 = 6
Number of sweets that Bobby had in the end
= 65 u
= 65 x 6
= 390
Number of sweets that Fred had in the end
= 78 u
= 78 x 6
= 468
Answer(s): (a) 390; (b) 468
