Wesley saved some 50-cent coins and $10 notes in his coin box. The total value of the 50-cent coins to the total value of the $10 notes he had was in the ratio 3 : 11. After $70 worth of 50-cent coins and an equal value of $10 notes were added to the coin box, the ratio of the total value of 50-cent coins to the total value of $10 notes became 5 : 9. How many of each type did Wesley have in the end?
- 50-cent coins?
- $10 notes?
|
Value of 50-cent |
Value of $10 |
Difference in value |
Before |
3x1 = 3 u |
11x1 = 11 u |
8x1 = 8 u |
Change |
+ 70 |
+ 70 |
|
After |
5x2 = 10 u |
9x2 = 18 u |
4x2 = 8 u |
(a)
The difference in values between 50-cent and $10 remains unchanged. Make the difference in value the same. LCM of 8 and 4 is 8.
Increase in the value of 50-cent coins after more were added
= 10 u - 3 u
= 7 u
7 u = 70
1 u = 70 ÷ 7 = 10
Value of 50-cent coins in the end
= 10 u
= 10 x 10
= $100
100¢ = $1
50¢ = $0.50
Number of 50-cent coins in the end
= 100 ÷ 0.50
= 200
(b)
Value of $10 notes in the end
= 18 u
= 18 x 10
= $180
Number of $10 notes in the end
= 180 ÷ 10
= 18
Answer(s): (a) 200; (b) 18