Mia bought 33 pencils and Daniel bought 57 pencils. After Daniel used
37 times as many pencils as Mia, he was left with four times as many pencils as Mia. How many pencils did each of them have in the end?
- Mia
- Daniel
| |
Make p the same.
(1)x4 = (3) |
Mia
(1) |
Daniel
(2) |
| Before |
132 |
33 |
57 |
| Change |
- 28 u |
- 7 u |
- 3 u |
| After |
4 p |
1 p |
4 p |
(a)
33 - 7 u = 1 p --- (1)
57 - 3 u =
4 p --- (2)
(1)
x4
132 - 28 u =
4 p --- (3)
(3) = (2)
57 - 3 u = 132 - 28 u
28 u - 3 u = 132 - 57
25 u = 75
1 u = 75 ÷ 25 = 3
Number of pencils that Mia had in the end
= 33 - 7 u
= 33 - 7 x 3
= 33 - 21
= 12
(b)
1 p = 12
Number of pencils that Daniel had in the end
= 4 p
= 4 x 12
= 48
Answer(s): (a) 12; (b) 48
