Peter, Cody and Owen had a total of 458 coins at first. After a week, the number of Peter's coins became 3 times the number of coins he had at first. The number of Cody's coins decreased by 250. Owen had one-quarter as many coins as he had at first. In the end, the three boys had the same number of coins.
- How many coins did Owen have at first?
- What was the total number of coins that the three boys had in the end?
|
Peter |
Cody |
Owen |
Total |
Before |
1 u |
3 u + 250 |
12 u |
|
Change |
x 3 |
- 250 |
x 14 |
|
After |
3 u |
3 u |
3 u |
9 u |
(a)
Total number of coins at first
=
1 u + 3 u + 250 + 12 u
= 16 u + 250
16 u + 250 = 45816 u = 458 - 25016 u = 208
1 u = 208 ÷ 16 = 13 Number of coins that Owen had at first
= 3 u ÷
14= 3 u x
41= 12 u = 12 x 13 = 156(b)Total number of coins that the three boys had at the end = 9 u = 9 x 13 = 117 Answer(s): (a) 156; (b) 117