Erika bought some necklaces and rings for her friends. The price of each necklace was $4.70 while the price of each ring was $14.50. For every 7 rings bought, she was given one such necklace for free. After receiving the free necklaces, the number of necklaces was ¹₅ of the number of rings bought. If Erika paid a total of $4652.10, how much more did she pay for the rings than the necklaces?

Rings	Necklaces
5x7	1x7
Bought	Free	Bought
7x5	1x5
35 u	5 u	2 u

	Rings	Necklaces
	Bought	Free	Bought
Number	35 u	5 u	2 u
Value	$14.50	0	$4.70
Total value	507.5 u	0	9.4 u

The number of rings bought is the repeated identity. Make the number of rings bought the same.  LCM of 5 and 7 is 35.

Cost of the bought rings
= 35 u x 14.50
= 507.5 u

Cost of the bought necklaces
= 2 u x 4.70  
= 9.4 u

Total cost of the bought items
= 507.5 u + 9.4 u
= 516.9 u

516.9 u = 4652.10

1 u = 4652.10 ÷ 516.90 = 9

Amount that she paid more for the rings than the necklaces
= 507.5 u - 9.4 u 
= 498.1 u
= 498.1 x 9
= $4482.90

Answer(s): $4482.90