Fiona had an equal number of dates and kiwis at first. She sold one-quarter of the kiwis and bought another 77 dates. In the end, she had five times as many dates as kiwis. Find the number of kiwis she had at first.
| |
Kiwis |
Dates |
| Before |
4 u |
15 u - 77 |
| Change |
- 1 u |
+ 77 |
| After |
3 u |
15 u |
The number of dates and kiwis at first is the same.
15 u - 77 = 4 u
15 u - 4 u = 77
11 u = 77
1 u = 77 ÷ 11 = 7
Number of kiwis that she had at first
= 4 u
= 4 x 7
= 28
Answer(s): 28
