Pierre and Sean had a total of $150. Pierre gave $13 to Sean. In return, Sean gave
17 of his money to Pierre. In the end, Pierre had four times as much money as Sean. How much money did Pierre have at first?
| |
Pierre |
Sean |
Total |
| Before |
|
|
$150 |
| Change 1 |
- $13 |
+ $13 |
|
| After 1 |
|
7 p |
|
| Change 2 |
+ 1 p |
- 1 p |
|
| After 2 |
|
6 p |
|
Comparing Pierre
and Sean
in the end |
4 u |
1 u |
$150 |
The total amount that Sean and Pierre had remains unchanged.
Total amount in the end
= 4 u + 1 u
= 5 u
5 u = 150
1 u = 150 ÷ 5 = 30
Amount that Pierre has in the end
= 4 u
= 4 x 30
= $120
Amount that Sean has in the end
= 1 u
= $30
6 p = 1 u = 30
1 p = 30 ÷ 6 = 5
Amount that Sean gave to Pierre
= 1 p
= 1 x 5
= $5
Amount that Pierre had at first
= 120 - 5 + 13
= $128
Answer(s): $128
