Dana places 4 packets an equal distance from one another. The distance between the first packet and the fourth packet is 150 cm. If Dana adds another 15 packets that are equal distance apart,
- How many gaps will there be between the fifteenth packet and the nineteenth packet?
- What is the distance between the 15th packet and the 19th packet?
(a)
Number of gaps between 4 packets
= 4 - 1
= 3
Distance between two packets
= 150 ÷ 3
= 50 cm
Number of gaps between the fifteenth and the nineteenth packet
= 19 - 15
= 4
(b)
Distance between the fifteenth and the nineteenth packet
= 4 x 50
= 200 cm
Answer(s): (a) 4; (b) 200 cm