The figure, not drawn to scale, is made up of 3 different triangles D, E and F. 15% of triangle D and 20% of triangle F is shaded. The shaded area of D is the same as the shaded area of F. What fraction of the figure is shaded if 25% of Triangle E is shaded?
Unshaded area of D |
Shaded area of D |
Unshaded area of F |
Shaded area of F |
17x1 |
3x1 |
4x3 |
1x3 |
17 u |
3 u |
12 u |
3 u |
15% =
15100 =
320 20% =
20100 =
15 25% =
25100 =
14The shaded area of D is the same as the shaded area of F.
Make the LCM of the shaded area of D and shaded area of F the same.
LCM of 3 and 1 = 3
14 of E is shaded
= Shaded area of D + Shaded area of F
= 3 u + 3 u
= 6 u
Fraction of E that is unshaded
= 1 -
14 =
34 14 of E = 6 u
34 of E = 3 x 6 u = 18 u
Fraction of the figure that is shaded if 25% of Triangle E is shaded
=
6 + 617 + 18 + 12 + 6 + 6=
1259 Answer(s):
1259