Machine A takes 8 minutes to cut 136 pieces of lumbers. Machine B takes 15 minutes to cut 105 pieces of lumbers. Machine C takes 10 minutes to cut 110 pieces of lumber.
- Which is the faster combination, A and B or B and C? (Eg A, B)
- In 1 minute, how many more pieces of lumbers can be cut by the faster combination compared to the other combination?
(a)
Time taken by Machine A alone:
8 min → 136 pieces
1 min → 136 ÷ 8 = 17 pieces
Time taken by Machine B alone:
15 min → 105 pieces
1 min → 105 ÷ 15 = 7 pieces
Time taken by Machine C alone:
10 min → 105 pieces
1 min → 110 ÷ 10 = 11 pieces
Time taken by Machine A and Machine B together:
1 min → 17 + 7 = 24 pieces
Time taken by Machine B and Machine C together:
1 min → 7 + 11 = 18 pieces
Machine A and B are the faster combination.
(b)
Number of more pieces of lumbers that can be cut by the faster combination (Machine A and B) in 1 minute
= 24 - 18
= 6
Answer(s): (a) A, B or B, A; (b) 6