At 14 35, Albert left Town H for Town J, driving at a speed of 66 km/h. At 17 35, Ken also left Town H for Town J driving at a certain speed. Both of them did not change their speed throughout the journey. At 19 35, both of them passed a farm that was 198 km away from Town J. How many minutes earlier did Ken reach Town J than Albert?

Distance that Albert travelled
= 5 x 66
= 330 km

Distance between Town H and Town J
= 330 + 198
= 528 km

Since Ken passed the farm at the same time as Albert, it means that Ken travelled 330 km in 2 hours.

Ken's speed during the journey
= 330 ÷ 2
= 165 km/h

Duration that Ken took to reach Town J after passing the farm
= 198 ÷ 165
= 1.2 h

Duration that Albert took to reach Town J after passing the farm
= 198 ÷ 66
= 3 h

Difference between the time they took to reach Town J
= 3 - 1.2
= 1.8 h

1 h = 60 min
1.8 h = 1.8 x 60 = 108 min

Ken reached Town J 108 minutes earlier than Albert.

Answer(s): 108 min