At 13 40, Perry left Town A for Town B, driving at a speed of 69 km/h. At 15 40, Henry also left Town A for Town B driving at a certain speed. Both of them did not change their speed throughout the journey. At 18 40, both of them passed a church that was 138 km away from Town B. How many minutes earlier did Henry reach Town B than Perry?

Distance that Perry travelled
= 5 x 69
= 345 km

Distance between Town A and Town B
= 345 + 138
= 483 km

Since Henry passed the church at the same time as Perry, it means that Henry travelled 345 km in 3 hours.

Henry's speed during the journey
= 345 ÷ 3
= 115 km/h

Duration that Henry took to reach Town B after passing the church
= 138 ÷ 115
= 1.2 h

Duration that Perry took to reach Town B after passing the church
= 138 ÷ 69
= 2 h

Difference between the time they took to reach Town B
= 2 - 1.2
= 0.8 h

1 h = 60 min
0.8 h = 0.8 x 60 = 48 min

Henry reached Town B 48 minutes earlier than Perry.

Answer(s): 48 min