At 10 55, Bryan left Town A for Town B, driving at a speed of 89 km/h. At 12 55, Howard also left Town A for Town B driving at a certain speed. Both of them did not change their speed throughout the journey. At 14 55, both of them passed a mall that was 267 km away from Town B. How many minutes earlier did Howard reach Town B than Bryan?

Distance that Bryan travelled
= 4 x 89
= 356 km

Distance between Town A and Town B
= 356 + 267
= 623 km

Since Howard passed the mall at the same time as Bryan, it means that Howard travelled 356 km in 2 hours.

Howard's speed during the journey
= 356 ÷ 2
= 178 km/h

Duration that Howard took to reach Town B after passing the mall
= 267 ÷ 178
= 1.5 h

Duration that Bryan took to reach Town B after passing the mall
= 267 ÷ 89
= 3 h

Difference between the time they took to reach Town B
= 3 - 1.5
= 1.5 h

1 h = 60 min
1.5 h = 1.5 x 60 = 90 min

Howard reached Town B 90 minutes earlier than Bryan.

Answer(s): 90 min