At 9 a.m., Flynn started from City E and travelled towards City F and his speed remained constant throughout. At 10 a.m., Zoe started her journey from City E towards City F at an average speed of 80 km/h. Zoe overtook Flynn at 2 p.m. After overtaking, Zoe carried on her journey at the same average speed and reached at City F at 3:15 p.m.

1. Find Flynn's average speed in km/h.
2. What is the distance between the two cities?

(a)
From 10 a.m. to 2 p.m. = 4 h

Distance that Zoe had travelled until Zoe overtook Flynn
= 4 x 80
= 320 km

From 9 a.m. to 2 p.m. = 5 h

Flynn's average speed
= 320 ÷ 5
= 64 km/h

(b)
From 10 a.m. to 3:15 p.m. = 5 h 15 min

1 h = 60 min
5 h 15 min = 5 ¹⁵ ₆₀
 h = 5 ¹₄ h

Distance between the two cities
= 5 ¹₄ x 80
= ²¹₄ x 80
= 420 km

Answer(s): (a) 64 km/h; (b) 420 km