City L and City M are 396 km apart. At 2.46 p.m., Asher is travelling at a uniform speed left City L for City M while Cody set off from City M to City L along the same road at a uniform speed, which was 6 km/h slower than that of Asher. The two met at 4.46 p.m.

1. Find the speed of Asher.
2. If Cody continued to travel at the same speed, how long would it take for him to reach his destination after the two met? Express your answer in mixed number.

(a)
Time taken for Asher and Cody to travel from 2.46 p.m. to 4.46 p.m. = 2 h

Average speed of Asher and Cody
= 396 ÷ 2
= 198 km/h

Asher's speed
= (198 + 6) ÷ 2
= 204 ÷ 2 
= 102 km/h

(b)
Cody's speed
= 102 - 6
= 96 km/h

Distance that Cody travelled in 2 h
= 2 x 96
= 192 km

Remaining distance that Cody needed to travel
= 396 - 192
= 204 km

Time that Cody needed to reach his destination after the two met
= 204 ÷ 96
= 2¹²₉₆
= 2¹₈ h

Answer(s): (a) 102 km/h; (b) 2¹₈ h