At 08 10, Usha left Town F and cycled towards Town G. Shiyun left Town F and cycled towards Town G at 08 30. Shiyun's cycling speed was 6 km/h faster than Usha. At 10 10, Shiyun caught up with Usha. Find the cycling speed of each cyclist.
- Usha
- Shiyun
(a)
Duration that Shiyun cycled from 08 30 to 10 10
= 1
4060 = 1
23 h
Distance that Shiyun cycled more than Usha
= 1
23 x 6
= 10 km
However, since Usha left 20 minutes earlier than Shiyun and Shiyun caught up with Usha, it means that Usha has cycled 10 km in 20 min.
1 h = 60 min
20 min = 20 ÷ 60 =
13 h
Usha's cycling speed
= 10 ÷
13 = 10 x
31 = 30 km/h
(b)
Shiyun's cycling speed
= 30 + 6
= 36 km/h
Answer(s): (a) 30 km/h ; (b) 36 km/h
