Adam has 3 times as many red stickers as green stickers.
After he gives away 34 green stickers,
Adam has 5 times as many red stickers as green stickers.
- How many more red stickers than green stickers does Adam have at first?
- How many less green stickers than red stickers does Adam have in the end?
|
Red |
Green |
Before |
3 x 5 = 15 u |
1 x 5 = 5 u |
Change |
No Change |
- 34 |
After |
5 x 3 = 15 u |
1 x 3 = 3 u |
(a)
The number of red stickers remains unchanged.
Make the number of red stickers and green stickers the same using LCM of 3 and 5.
LCM of 3 and 5 = 15
Number of green stickers that Adam gives away
= 5 u - 3 u
= 2 u
2 u = 34
1 u = 34 ÷ 2 = 17
Number of more red stickers than green stickers at first
= 15 u - 5 u
= 10 u
= 10 x 17
= 170
(b)
Number of less green stickers than red stickers in the end
= 15 u - 3 u
= 12 u
= 12 x 17
= 204
Answer(s): (a) 170; (b) 204