Bryan and Adam have a total of 400 stickers.
Bryan gives Adam 10 stickers.
Now, Bryan has 40 more than Adam.
- How many stickers does Bryan have at first?
- How many stickers does Adam have in the end?
|
Bryan |
Adam |
Total |
Before |
1 u + 50 |
1 u - 10 |
400 |
Change |
- 10 |
+ 10 |
|
After |
1 u + 40 |
1 u |
2 u + 40 |
(a)
In the end
Number of stickers that Bryan has = 1 u + 40
Number of stickers that Adam has = 1 u
Total number of stickers = 1 u + 1 u + 40 = 2 u + 40
At first
Number of stickers that Bryan has = 1 u + 40 + 10 = 1 u + 50
Number of stickers that Adam has = 1 u - 10
The total number of stickers at first and in the end remains unchanged.
Total number of stickers in the end = Total number of stickers at first
2 u + 40 = 400
2 u = 400 - 40
2 u = 360
1 u = 360 ÷ 2 = 180
Number of stickers that Bryan has at first
= 1 u + 50
= 180 + 50
= 230
(b)
Number of stickers that Adam has in the end
= 1 u
= 180
Answer(s): (a) 230; (b) 180