Charlie and Adam have some stickers in the ratio of 5 : 4.
When Charlie gives away 60 stickers,
the ratio of the stickers becomes 7 : 8.
- How many stickers do they have at first?
- How many stickers do they have in the end?
|
Charlie |
Adam |
Before |
5 x 2 = 10 u |
4 x 2 = 8 u |
Change |
- 60 |
No change |
After |
7 x 1 = 7 u |
8 x 1 = 8 u |
(a)
The number of stickers that Adam has remains unchanged.
Make the number of stickers that Adam has the same using LCM of 4 and 8.
LCM of 4 and 8 = 8
Number of stickers that Charlie gives away
= 10 u - 7 u
= 3 u
3 u = 60
1 u = 60 ÷ 3 = 20
Number of stickers that they have at first
= 10 u + 8 u
= 18 u
= 18 x 20
= 360
(b)
Number of stickers that they have in the end
= 7 u + 8 u
= 15 u
= 15 x 20
= 300
Answer(s): (a) 360; (b) 300