Adam has some blue stickers and red stickers.
If Adam receives another 40 blue stickers,
the blue stickers will be 25% as many as the red stickers.
If Adam gives away 412 red stickers,
the blue stickers will be 60% as many as the red stickers.
- How many blue stickers are there?
- How many red stickers are there?
|
Scenario 1 |
Scenario 2 |
|
Green |
Red |
Green |
Red |
Before |
1 u - 40 |
4 u |
3 p |
5 p + 412 |
Change |
+ 40 |
No change |
No change |
- 412 |
After |
1 u |
4 u |
3 p |
5 p |
(a)
25% =
25100 =
14 60% =
60100 =
35 Scenario 1 Number of green stickers at first = 1 u - 40
Number of red stickers at first = 4 u
Scenario 2 Number of green stickers at first = 3 p
Number of red stickers at first = 5 p + 412
1 u - 40 = 3 p --- (1)
4 u = 5 p + 412 --- (2)
From (1)1 u = 40 + 3 p --- (3) (3) x 44 u = 160 + 12 p --- (4)
(4) = (2)160 + 12 p = 5 p + 412 12 p - 5 p = 412 - 1607 p = 252
1 p = 252 ÷ 7 = 36
Number of blue stickers = 3 p = 3 x 36 = 108 (b) Number of red stickers = 5 p + 412 = 5 x 36 + 412
= 180 + 412= 592 Answer(s): (a) 108; (b) 592