Adam has some red stickers and blue stickers.
If 335 red stickers are added, 40% of the stickers will be blue stickers.
If 199 blue stickers are added, 25% of the stickers will be red stickers.
- How many red stickers are there?
- How many blue stickers are there?
|
Scenario 1 |
Scenario 2 |
|
Red |
Blue |
Red |
Blue |
Before |
3 u - 335 |
2 u |
1 p |
3 p - 199 |
Change |
+ 335 |
No change |
No change |
+ 199 |
After |
3 u |
2 u |
1 p |
3 p |
(a)
40% =
40100 =
25 25% =
25100 =
14 Scenario 1 Fraction of the stickers that are red
= 1 -
25 =
35 Number of red stickers at first = 3 u - 335
Number of blue stickers at first = 2 u
Scenario 2 Fraction of the stickers that are blue
= 1 -
14=
34 Number of red stickers at first = 1 p
Number of blue stickers at first = 3 p - 199
3 u - 335 = 1 p --- (1)
2 u = 3 p - 199
2 u + 199 = 3 p --- (2)
(1)
x 3 9 u - 1005 = 3 p --- (3)
(3) = (2)
9 u - 1005 = 2 u + 199
9 u - 2 u = 1005 + 199
7 u = 1204
1 u = 1204 ÷ 7 = 172
Number of red stickers
= 3 u - 335
= 3 x 172 - 335
= 516 - 335
= 181
(b)
Number of blue stickers
= 2 u
= 2 x 172
= 344
Answer(s): (a) 181; (b) 344