Pamela had some passion fruits and mangoes in 2 containers. In Container E, the number of passion fruits to the number of mangoes was in the ratio of 5 : 6. In Container F, there were twice as many passion fruits as mangoes. After Pamela transferred ²₃ of the mangoes from Container E to Container F, the number of fruits left in Container E was 105 and the ratio of the number of passion fruits to the number of mangoes in Container B became 6 : 7. How many fruits were in Container F in the end?

	Container E		Container F
	Passion Fruits	Mangoes	Passion Fruits	Mangoes
Before	5 u	6 u	2x3 =  6 p	1x3 = 3 p
Change		- 4 u		+ 4 u (+ 4 p)
After	5 u	2 u	6x1 = 6 p	7x1 = 7 p

Number of mangoes that Pamela transferred from Container E to Container F
= ²₃ x 6 u
= 4 u

Total number of fruits in Container E in the end
= 5 u + 2 u
= 7 u

7 u = 105
1 u = 105 ÷ 7 = 15

The number of passion fruits in Container F is the unchanged quantity.
LCM of 2 and 6 is 6.

Number of mangoes that Pamela transferred from Container E to Container F
= 4 u
= 4 x 15
= 60

Increase in the number of mangoes that due to the transfer from Container E to Container F
= 7 p - 3 p
= 4 p

4 p = 4 u 
4 p = 60

1 p = 60 ÷ 4 = 15

Number of fruits in Container F in the end
= 6 p + 7 p
= 13 p
= 13 x 15
= 195

Answer(s): 195