Linda had some lemons and chikoos in 2 cartons. In Carton W, the number of lemons to the number of chikoos was in the ratio of 3 : 10. In Carton X, there were twice as many lemons as chikoos. After Linda transferred
35 of the chikoos from Carton W to Carton X, the number of fruits left in Carton W was 182 and the ratio of the number of lemons to the number of chikoos in Carton B became 3 : 8. How many fruits were in Carton X in the end?
|
Carton W |
Carton X |
|
Lemons |
Chikoos |
Lemons |
Chikoos |
Before |
3 u |
10 u |
2x3 = 6 p |
1x3 = 3 p |
Change |
|
- 6 u |
|
+ 6 u (+ 13 p) |
After |
3 u |
4 u |
3x2 = 6 p |
8x2 = 16 p |
Number of chikoos that Linda transferred from Carton W to Carton X
=
35 x 10 u
= 6 u
Total number of fruits in Carton W in the end
= 3 u + 4 u
= 7 u
7 u = 182
1 u = 182 ÷ 7 = 26
The number of lemons in Carton X is the unchanged quantity.
LCM of 2 and 3 is 6.
Number of chikoos that Linda transferred from Carton W to Carton X
= 6 u
= 6 x 26
= 156
Increase in the number of chikoos that due to the transfer from Carton W to Carton X
= 16 p - 3 p
= 13 p
13 p = 6 u
13 p = 156
1 p = 156 ÷ 13 = 12
Number of fruits in Carton X in the end
= 6 p + 16 p
= 22 p
= 22 x 12
= 264
Answer(s): 264