Irene had some lemons and kiwis in 2 containers. In Container M, the number of lemons to the number of kiwis was in the ratio of 4 : 9. In Container N, there were twice as many lemons as kiwis. After Irene transferred
23 of the kiwis from Container M to Container N, the number of fruits left in Container M was 266 and the ratio of the number of lemons to the number of kiwis in Container B became 6 : 7. How many fruits were in Container N in the end?
|
Container M |
Container N |
|
Lemons |
Kiwis |
Lemons |
Kiwis |
Before |
4 u |
9 u |
2x3 = 6 p |
1x3 = 3 p |
Change |
|
- 6 u |
|
+ 6 u (+ 4 p) |
After |
4 u |
3 u |
6x1 = 6 p |
7x1 = 7 p |
Number of kiwis that Irene transferred from Container M to Container N
=
23 x 9 u
= 6 u
Total number of fruits in Container M in the end
= 4 u + 3 u
= 7 u
7 u = 266
1 u = 266 ÷ 7 = 38
The number of lemons in Container N is the unchanged quantity.
LCM of 2 and 6 is 6.
Number of kiwis that Irene transferred from Container M to Container N
= 6 u
= 6 x 38
= 228
Increase in the number of kiwis that due to the transfer from Container M to Container N
= 7 p - 3 p
= 4 p
4 p = 6 u
4 p = 228
1 p = 228 ÷ 4 = 57
Number of fruits in Container N in the end
= 6 p + 7 p
= 13 p
= 13 x 57
= 741
Answer(s): 741