PSLE
Shiyun and Hilda folded paper stars over two days. On Thursday, Shiyun folded 18 paper stars more than Hilda. On Friday, Shiyun folded another 30 paper stars and Hilda folded another 20. At the end of the two days, Shiyun made ⁵₈ of the total number of stars. What was the number of paper stars that Hilda folded?

	Shiyun	Hilda	Difference
Before	1 u + 18	1 u	18
Change	+ 30	+ 20
After	1 u + 48	1 u + 20	28
Comparing between Shiyun and Hilda in the end	5 p	3 p	2 p

Difference between the number of paper stars that Shiyun and Hilda folded in the end is repeated.

Difference between the number of paper stars that Shiyun and Hilda folded in the end
= 5 p - 3 p
= 2 p

Difference between the number of paper stars that Shiyun and Hilda folded in the end
= (1 u + 48) - (1 u + 20)
= 1 u + 48 - 1 u - 20
= 48 - 20
= 28

2 p = 28

1 p = 28 ÷ 2 = 14

Number of paper stars that Hilda folded
= 3 p
= 3 x 14
= 42

Answer(s): 42