PSLE Bobby kept his red and blue buttons in two boxes. The ratio of the number of red to blue buttons in the first box was 1 : 5 and it was 1 : 2 in the second box. The two boxes contained the same number of buttons. What fraction of Bobby's buttons were blue buttons?
First box |
Second box |
1x6 6 u |
1x6 6 u |
6x1 |
3x2 |
Red |
Blue |
Red |
Blue |
1x1 |
5x1 |
1x2 |
2x2 |
1 u |
5 u |
2 u |
4 u |
The total number of buttons in the first box and the second box is the same. Make the total number of buttons in each box the same.
LCM of 6 and 3 is 6.
Total number of blue buttons
= 5 u + 4 u
= 9 u
Total number of buttons
= 6 u + 6 u
= 12 u
Fraction of Bobby's buttons that were blue buttons
=
912 =
34 Answer(s):
34