PSLE At a basketball match, 35% of the tickets were sold at full price and 60% of the tickets at half price. The remaining 40 tickets were given away free. The total amount of money collected was $23920. What was the price of the ticket at half price?
Percentage of the tickets given free
= 100% - 35% - 60%
= 5%
5% → 40
1% → 40 ÷ 5 = 8
Number of tickets sold at full price
= 35% of the tickets
= 35 x 8
= 280
Number of tickets sold at half price
= 60% of the tickets
= 60 x 8
= 480
|
Full price |
Half price |
Free |
Total |
Number |
280 |
480 |
40 |
|
Value |
2 u |
1 u |
|
|
Total value |
560 u |
480 u |
|
1040 u |
Cost of 1 full price ticket = 2 u
Cost of 1 half price ticket = 1 u
Total amount collected
= 280 x 2 u + 480 x 1 u
= 560 u + 480 u
= 1040 u
1040 u = 23920
1 u = 23920 ÷ 1040 = 23
Price of the ticket at half price
= 1 u
= $23
Answer(s): $23