PSLE At a basketball match, 45% of the tickets were sold at full price and 40% of the tickets at half price. The remaining 90 tickets were given away free. The total amount of money collected was $15600. What was the full price of the ticket?
Percentage of the tickets given free
= 100% - 45% - 40%
= 15%
15% → 90
1% → 90 ÷ 15 = 6
Number of tickets sold at full price
= 45% of the tickets
= 45 x 6
= 270
Number of tickets sold at half price
= 40% of the tickets
= 40 x 6
= 240
|
Full price |
Half price |
Free |
Total |
Number |
270 |
240 |
90 |
|
Value |
2 u |
1 u |
|
|
Total value |
540 u |
240 u |
|
780 u |
Cost of 1 full price ticket = 2 u
Cost of 1 half price ticket = 1 u
Total amount collected
= 270 x 2 u + 240 x 1 u
= 540 u + 240 u
= 780 u
780 u = 15600
1 u = 15600 ÷ 780 = 20
Full price of the ticket
= 2 u
= 2 x 20
= $40
Answer(s): $40