PSLEIn the figure, NPQR is a straight line, PRST is a parallelogram and SQ = ST. ∠TNP is a right angle, ∠NTP = 35° and ∠RSQ = 19°.
- Find ∠u.
- Find ∠v.
(a)
∠TNP = 90° (Right angle)
∠u
= 90° + 35°
= 125° (Exterior angle of a triangle)
(b)
∠RST = ∠RPT = 125° (Parallelogram)
∠QST
= 125° - 19°
= 106°
∠v
= (180° - 106°) ÷ 2
= 37° (Isosceles triangle)
Answer(s): (a) 125°; (b) 37°