PSLE In the figure, QRST is a parallelogram. NTQ and PTS are straight lines and NP = PQ. ∠NPT = 31° and ∠RST = 55°.
- Find ∠STQ.
- Find ∠TPQ.
(a)
∠STQ
= 180° - 55°
= 125° (Interior angles)
(b)
∠NTP
= ∠STQ
= 125° (Vertically opposite angles)
∠PNT
= 180° - 125° - 31°
= 24° (Angles sum of triangle)
∠PQT = ∠PNT (Isosceles triangle)
∠NPQ
= 180° - 24° - 24°
= 132° (Angles sum of triangle)
∠TPQ
= 132° - 31°
= 101°
Answer(s): (a) 125°; (b) 101°