Ian and Neave each had the same volume of water. The water was used to pour into identical bottles. Ian filled up 14 bottles and had 2 ℓ of water left. Neave filled up 10 bottles and had 2.48 ℓ of water left.
- What was the capacity of each bottle? Give your answer in millilitres.
- What was the total volume of water Ian and Neave had at first? Give your answer in litres.
(a)
Let 1 B be the volume of 1 bottle of water.
Volume of water that Ian had = 14 B + 2 --- (1)
Volume of water that Neave had = 10 B + 2.48 --- (2)
The volume of water that Ian and Neave have is the same.
(1) = (2)
14 B + 2 = 10 B + 2.48
14 B - 10 B = 2.48 - 2
4 B = 0.48
1 B = 0.48 ÷ 4 = 0.12
1 ℓ = 1000 mℓ
0.12 ℓ = 0.12 x 1000 = 120 mℓ
(b)
Volume of 14 bottles
= 14 x 0.12
= 1.68 ℓ
Volume of water that Ian had at first
= 14 B + 2
= 14 x 0.12 + 2
= 1.68 + 2
= 3.68 ℓ
Total volume of water that Ian and Neave had at first
= 2 x 3.68
= 7.36 ℓ
Answer(s): (a) 120 mℓ; (b) 7.36 ℓ
