Helen spent $98 on a dress. She spent
211 of her remaining money on a windbreaker and a sweater, after which half her money was left.
- What fraction of her money did she spend on the dress?
- The cost of the sweater is 16 the cost of the windbreaker. How much more does the windbreaker cost than the sweater?
Dress |
Remaining amount |
|
Windbreaker |
Sweater |
Left |
$98 |
2 |
9 |
1x9 |
1x9 |
7 u |
2 u |
9 u |
(a)
The amount of money left is repeated. Make the numerators the same LCM of 1 and 9 is 9.
1x92x9 of total money =
911 of remaining amount
918 of total money =
911 of remaining amount
Fraction of her money that she spent on the dress
=
DressTotal =
718 (b)
Cost of the dress = 7 u
7 u = 98
1 u = 98 ÷ 7 = 14
Cost of the windbreaker and the sweater
= 2 u
= 2 x 14
= $28
Cost of the sweater = 1 p
Cost of the windbreaker = 6 p
Total cost of the sweater and the windbreaker
= 1 p + 6 p
= 7 p
7 p = 28
1 p = 28 ÷ 7 = 4
Amount that the windbreaker was more than the sweater
= 6 p - 1 p
= 5 p
= 5 x 4
= $20
Answer(s): (a)
718; (b) $20