Neave bought some coupons for a funfair. He used
37 of the coupons on games and
27 of the remainder on food. He bought another 80 coupons and had 22 more coupons than he had at first. How many coupons did he have at first?
| Games |
Remainder |
Bought |
Total |
3x7 =
21 u |
4x7 =
28 u |
|
7x7 =
49 u |
| |
Food |
Left |
|
|
| |
2x4 |
5x4 |
|
|
| 21 u |
8 u |
20 u |
80 |
49 u |
The remaining number of coupons before Neave bought another 80 coupons is repeated. Make the remaining number of coupons the same. LCM of 4 and 7 is 28.
Total number of coupons at first = 49 u
Total number of coupons in the end = 20 u + 80
Number of coupons left was 22 more than the number of coupons at first.
49 u + 22 = 20 u + 80
49 u - 20 u = 80 - 22
29 u = 58
1 u = 58 ÷ 29 = 2
Total number of coupons at first
= 49 u
= 49 x 2
= 98
Answer(s): 98
